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LibJS: Disallow 'return' outside of a function

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Matthew Olsson 2020-10-07 11:33:48 -07:00 • committed by Andreas Kling
parent 5feb7e8d28
commit 9a82c22a85
Notes: sideshowbarker 2024-07-19 01:58:35 +09:00
2 changed files with 6 additions and 0 deletions
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5
Libraries/LibJS/Parser.cpp
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@ -396,6 +396,7 @@ RefPtr<FunctionExpression> Parser::try_parse_arrow_function_expression(bool expe
bool is_strict = false;
auto function_body_result = [&]() -> RefPtr<BlockStatement> {
TemporaryChange change(m_parser_state.m_in_function_context, true);
if (match(TokenType::CurlyOpen)) {
// Parse a function body with statements
return parse_block_statement(is_strict);
@ -1202,6 +1203,9 @@ NonnullRefPtr<NewExpression> Parser::parse_new_expression()
NonnullRefPtr<ReturnStatement> Parser::parse_return_statement()
{
if (!m_parser_state.m_in_function_context)
syntax_error("'return' not allowed outside of a function");
consume(TokenType::Return);
// Automatic semicolon insertion: terminate statement when return is followed by newline
@ -1315,6 +1319,7 @@ NonnullRefPtr<FunctionNodeType> Parser::parse_function_node(bool check_for_funct
function_length = parameters.size();
bool is_strict = false;
TemporaryChange change(m_parser_state.m_in_function_context, true);
auto body = parse_block_statement(is_strict);
body->add_variables(m_parser_state.m_var_scopes.last());
body->add_functions(m_parser_state.m_function_scopes.last());