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AK: Don't implicitly convert Optional<T&> to Optional<T>

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C++ will jovially select the implicit conversion operator, even if it's
complete bogus, such as for unknown-size types or non-destructible
types. Therefore, all such conversions (which incur a copy) must
(unfortunately) be explicit so that non-copyable types continue to work.

NOTE: We make an exception for trivially copyable types, since they
are, well, trivially copyable.

Co-authored-by: kleines Filmröllchen <filmroellchen@serenityos.org>
This commit is contained in:
Jonne Ransijn 2024-11-25 13:23:31 +01:00 • committed by Ali Mohammad Pur
commit d7596a0a61
Notes: github-actions[bot] 2024-12-04 00:59:23 +00:00
22 changed files with 118 additions and 40 deletions
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2
Libraries/LibHTTP/HeaderMap.h
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@ -39,7 +39,7 @@ public:
return m_map.contains(name);
}
[[nodiscard]] Optional<ByteString> get(ByteString const& name) const
[[nodiscard]] Optional<ByteString const&> get(ByteString const& name) const
{
return m_map.get(name);
}