AK: Don't implicitly convert Optional<T&> to Optional<T>

C++ will jovially select the implicit conversion operator, even if it's
complete bogus, such as for unknown-size types or non-destructible
types. Therefore, all such conversions (which incur a copy) must
(unfortunately) be explicit so that non-copyable types continue to work.

NOTE: We make an exception for trivially copyable types, since they
are, well, trivially copyable.

Co-authored-by: kleines Filmröllchen <filmroellchen@serenityos.org>
This commit is contained in:
Jonne Ransijn 2024-11-25 13:23:31 +01:00 committed by Ali Mohammad Pur
parent 8468fb9ae5
commit d7596a0a61
Notes: github-actions[bot] 2024-12-04 00:59:23 +00:00
22 changed files with 118 additions and 40 deletions

View file

@ -197,7 +197,7 @@ static auto const& ensure_currency_codes()
return currency_codes;
}
Optional<CurrencyCode> get_currency_code(StringView currency)
Optional<CurrencyCode const&> get_currency_code(StringView currency)
{
static auto const& currency_codes = ensure_currency_codes();
return currency_codes.get(currency);