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AK: Don't implicitly convert Optional<T&> to Optional<T>
C++ will jovially select the implicit conversion operator, even if it's complete bogus, such as for unknown-size types or non-destructible types. Therefore, all such conversions (which incur a copy) must (unfortunately) be explicit so that non-copyable types continue to work. NOTE: We make an exception for trivially copyable types, since they are, well, trivially copyable. Co-authored-by: kleines Filmröllchen <filmroellchen@serenityos.org>
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Notes:
github-actions[bot]
2024-12-04 00:59:23 +00:00
Author: https://github.com/yyny
Commit: d7596a0a61
Pull-request: https://github.com/LadybirdBrowser/ladybird/pull/2567
Reviewed-by: https://github.com/alimpfard
Reviewed-by: https://github.com/gmta ✅
22 changed files with 118 additions and 40 deletions
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@ -197,7 +197,7 @@ static auto const& ensure_currency_codes()
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return currency_codes;
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}
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Optional<CurrencyCode> get_currency_code(StringView currency)
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Optional<CurrencyCode const&> get_currency_code(StringView currency)
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{
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static auto const& currency_codes = ensure_currency_codes();
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return currency_codes.get(currency);
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