ladybird/Libraries/LibJS/Tests/builtins/BigInt/BigInt.asIntN.js
Jess 12cbefbee7 LibJS+LibCrypto: Use a bitwise approach for BigInt's as*IntN methods
This speeds up expressions such as `BigInt.asIntN(0x4000000000000, 1n)`
(#3615). And those involving very large bigints.
2025-03-20 09:44:12 +01:00

98 lines
3.8 KiB
JavaScript

describe("errors", () => {
test("invalid index", () => {
expect(() => {
BigInt.asIntN(-1, 0n);
}).toThrowWithMessage(RangeError, "Index must be a positive integer");
expect(() => {
BigInt.asIntN(Symbol(), 0n);
}).toThrowWithMessage(TypeError, "Cannot convert symbol to number");
});
test("invalid BigInt", () => {
expect(() => {
BigInt.asIntN(1, 1);
}).toThrowWithMessage(TypeError, "Cannot convert number to BigInt");
expect(() => {
BigInt.asIntN(1, Symbol());
}).toThrowWithMessage(TypeError, "Cannot convert symbol to BigInt");
expect(() => {
BigInt.asIntN(1, "foo");
}).toThrowWithMessage(SyntaxError, "Invalid value for BigInt: foo");
});
});
describe("correct behavior", () => {
test("length is 2", () => {
expect(BigInt.asIntN).toHaveLength(2);
});
test("basic functionality", () => {
expect(BigInt.asIntN(0, -2n)).toBe(0n);
expect(BigInt.asIntN(0, -1n)).toBe(0n);
expect(BigInt.asIntN(0, 0n)).toBe(0n);
expect(BigInt.asIntN(0, 1n)).toBe(0n);
expect(BigInt.asIntN(0, 2n)).toBe(0n);
expect(BigInt.asIntN(1, -3n)).toBe(-1n);
expect(BigInt.asIntN(1, -2n)).toBe(0n);
expect(BigInt.asIntN(1, -1n)).toBe(-1n);
expect(BigInt.asIntN(1, 0n)).toBe(0n);
expect(BigInt.asIntN(1, 1n)).toBe(-1n);
expect(BigInt.asIntN(1, 2n)).toBe(0n);
expect(BigInt.asIntN(1, 3n)).toBe(-1n);
expect(BigInt.asIntN(2, -3n)).toBe(1n);
expect(BigInt.asIntN(2, -2n)).toBe(-2n);
expect(BigInt.asIntN(2, -1n)).toBe(-1n);
expect(BigInt.asIntN(2, 0n)).toBe(0n);
expect(BigInt.asIntN(2, 1n)).toBe(1n);
expect(BigInt.asIntN(2, 2n)).toBe(-2n);
expect(BigInt.asIntN(2, 3n)).toBe(-1n);
expect(BigInt.asIntN(4, -3n)).toBe(-3n);
expect(BigInt.asIntN(4, -2n)).toBe(-2n);
expect(BigInt.asIntN(4, -1n)).toBe(-1n);
expect(BigInt.asIntN(4, 0n)).toBe(0n);
expect(BigInt.asIntN(4, 1n)).toBe(1n);
expect(BigInt.asIntN(4, 2n)).toBe(2n);
expect(BigInt.asIntN(4, 3n)).toBe(3n);
const extremelyBigInt = 123456789123456789123456789123456789123456789123456789n;
expect(BigInt.asIntN(0, extremelyBigInt)).toBe(0n);
expect(BigInt.asIntN(1, extremelyBigInt)).toBe(-1n);
expect(BigInt.asIntN(2, extremelyBigInt)).toBe(1n);
expect(BigInt.asIntN(4, extremelyBigInt)).toBe(5n);
expect(BigInt.asIntN(128, extremelyBigInt)).toBe(-99061374399389259395070030194384019691n);
expect(BigInt.asIntN(256, extremelyBigInt)).toBe(extremelyBigInt);
expect(BigInt.asIntN(0, -extremelyBigInt)).toBe(0n);
expect(BigInt.asIntN(1, -extremelyBigInt)).toBe(-1n);
expect(BigInt.asIntN(2, -extremelyBigInt)).toBe(-1n);
expect(BigInt.asIntN(4, -extremelyBigInt)).toBe(-5n);
expect(BigInt.asIntN(128, -extremelyBigInt)).toBe(99061374399389259395070030194384019691n);
expect(BigInt.asIntN(256, -extremelyBigInt)).toBe(-extremelyBigInt);
});
test("large bit values", () => {
expect(BigInt.asIntN(0x4000000000000, 1n)).toBe(1n);
expect(BigInt.asIntN(0x8ffffffffffff, 1n)).toBe(1n);
expect(BigInt.asIntN(2 ** 53 - 1, 2n)).toBe(2n);
// These incur large intermediate values that 00M. For now, ensure they don't crash
expect(() => {
BigInt.asIntN(0x4000000000000, -1n);
}).toThrowWithMessage(InternalError, "Out of memory");
expect(() => {
BigInt.asIntN(0x8ffffffffffff, -1n);
}).toThrowWithMessage(InternalError, "Out of memory");
expect(() => {
BigInt.asIntN(2 ** 53 - 1, -2n);
}).toThrowWithMessage(InternalError, "Out of memory");
});
});