ladybird/Userland/cal.cpp
Andrés Vieira f8a0eb616c Userland: Add the cal command (#838)
This is a very simple implementation of the cal command to display
a calendar into the command line.

For now this only prints the current month highlighting the current
day.
2019-12-02 15:22:55 +01:00

49 lines
1.3 KiB
C++

#include <stdio.h>
#include <time.h>
int day_of_week(int day, int month, int year)
{
static const int seek_table[] = { 0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4 };
if (month < 3)
--year;
return (year + year / 4 - year / 100 + year / 400 + seek_table[month - 1] + day) % 7;
}
int get_number_of_days(int month, int year)
{
bool is_leap_year = ((year % 400 == 0) || (year % 4 == 0 && year % 100 != 0));
bool is_long_month = (month == 1 || month == 3 || month == 5 || month == 7 || month == 8 || month == 10 || month == 12);
if (month == 2)
return is_leap_year ? 29 : 28;
return is_long_month ? 31 : 30;
}
int main(int argc, char** argv)
{
(void)argc;
(void)argv;
time_t now = time(nullptr);
auto* tm = localtime(&now);
int target_day = tm->tm_mday;
int target_month = tm->tm_mon + 1;
int target_year = tm->tm_year + 1900;
int target_day_of_week = day_of_week(1, target_month, target_year);
printf(" %02u - %04u \n", target_month, target_year);
printf("Su Mo Tu We Th Fr Sa\n");
for (int i = 1; i <= get_number_of_days(target_month, target_year); ++i) {
if (i < target_day_of_week) {
printf(" ");
} else {
printf(i != target_day ? "%2d" : "\x1b[30;47m%2d\x1b[0m", i);
}
printf(i % 7 == 0 ? "\n" : " ");
}
printf("\n\n");
}